8lz1q (8lz1q) asked a question.
Okta Expression Language, String Comparison
http://developer.okta.com/reference/okta_expression_language/index I am using the Okta Expression Language in an attempting to test if users last name is in A-L or M-Z and put them into a group based on that test -- (that is the simplified test) As I look through the documentation, **STRING** expressions do not appear to include the operators <, >, <=, and >=. Here are the test that I know work Test users last name: A-LArrays.contains({"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L"}, user.CustomVariable_LastName_CharSplit))Arrays.contains({"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L"}, user.CustomVariable_LastName_CharSplit)) == true Test users last name: M-ZArrays.contains({"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L"}, user.CustomVariable_LastName_CharSplit)) == falseArrays.contains({"M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"}, user.CustomVariable_LastName_CharSplit) user.CustomVariable_LastName_CharSplit contains only the capitalized letter of their last name. Is there an easier way to perform a conditional test of the user's last name to split them off into different groups? Thank you, W.
Hello!
We added this to our ideas. Thanks for your contribution!